# Resistor enclosed between the same node

I am sorry but I have no idea on how to rephrase my question, this is the best I could come up with.

But as they say, a picture is worth a thousand words.

As you can see, the 2K resistor is "enclosed between the same node" for the lack of a better expression on my behalf, namely node (b). How would I treat this resistor?

To give some background information, this is for my Principles of Electrical Engineering course, all my previous knowledge of circuitry is from my Physics II course, and I must add that my professor did NOT do a good job in explaining basic circuit analysis.

Now back to the subject at hand, we are being asked to find the equivalent resistor and I could do that just fine. The thing is when I looked up the solution manual that the professor handed us, she had bypassed the 2K resistor but offered no explanation as to why she did that and I am assuming it is because the resistor is situated between node (b) on either ends.

Could someone be kind enough and explain to me what is happening and how should I treat such situation in the future?

EDIT: Thanks to everyone who took their time to explain the concept to me. You guys are great. I get it now.

• You can look at it as 2 resistors in parallel. One is 2K and the other is 0 ohms. Now, using the formula for parallel resistors, what's the resistance of the parallel combination? What can you replace the 2K resistor with? – John D Sep 7 '16 at 2:41
• The current through the resistor is 0, so you can replace it with an open-circuit if that makes it easier. The voltage across the resistor is also 0, so you can replace it with a short circuit if you prefer. – mkeith Sep 7 '16 at 4:24
• When this kind of doubt come to you a good advice is to give name to all the nodes, then start to reduce nodes that are equals (shorted), and finally redraw circuit. Often all things become clear. – Antonio Sep 7 '16 at 7:29
• @Antonio that is what I usually do and I got to admit it does simplify things A LOT. I simply did not know what it meant to have the same resistor touching the same node in both ends such as is the case here, but now I get it. – Moe Odeh Sep 7 '16 at 19:18