So I want to know if my motor is fast enough for my project and the tutorial says: 100 RPM. On the datasheet it says: "No load speed:6600±10%rpm". Is this fast enough? I know it means without a load but it's a tiny load.

  • \$\begingroup\$ Welcome to EE.SE, Noah, but you need to clarify your question. 6600 RPM is 66 x 100 RPM. It would seem most obvious that this is way too fast for your application. What is your real question? Put all the details in your question and not in the comments. \$\endgroup\$ – Transistor Sep 28 '16 at 20:32
  • \$\begingroup\$ It means that motor needs something like 50:1 speed reduction gearbox to match your application. (Would be 66:1 but it'll slow down some under load) \$\endgroup\$ – Brian Drummond Sep 28 '16 at 20:33
  • \$\begingroup\$ You will have to explain your application a bit better. If your tutorial is freely accessible online, please post a link to it so we can help you. If not, please update your post with the details so we can better help you. \$\endgroup\$ – Mister Tea Sep 28 '16 at 21:03

That motor is 66 times as fast as required for your project: 6600 RPM vs 100 RPM.

| improve this answer | |
  • \$\begingroup\$ But what does the ±10% mean \$\endgroup\$ – Noah Sep 28 '16 at 20:39
  • 2
    \$\begingroup\$ @Noah The ±10% means that the no load speed can vary from 5940 RPM to 7260 RPM depending on the motor. The reason is since the motor is a low cost device, the manufacturing process allows for some variation as not every motor can be built exactly the same for economic reasons. \$\endgroup\$ – Mister Tea Sep 28 '16 at 20:59

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.