# How to simplify a circuit with ideal current source and ideal voltage source?

I'm currently trying to gain an understanding of Thévenin and Norton equivalent circuits and I've run into a circuit I simply don't understand. I've been researching online, but I've just run into contradictory information that often isn't helpful to begin with.

Here's the circuit:

I could simplify this circuit, but that ideal current source is my big roadblock. I'm currently trying to find the voltage between A and B.

I don't even know where to start. If someone could show me the right direction, that would be great! Thanks

• If you don't see any clever ways to simplify the circuit, you can just resort to superposition. Commented Oct 4, 2016 at 4:23
• The voltage betwen A and B is simply 3A x 48 Ohm Commented Oct 4, 2016 at 7:35
• If you replace the current source with open circuit (because its internal impedance is infinity, theoretically) then you'll see that the voltage across 48Ohm resistor is not affected by 5V voltage source. Thus, as @ClaudioAviChami stated, voltage across 48Ohm resistor is simply 3A x 48Ohm. Commented Oct 4, 2016 at 19:46