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I am very new to Eagle. I was drawing a schematic that would connect my AVR Dragon to my Atmega32A. I drew this up and switched to board layout. enter image description here

The problem is in board layout. It seems to me that VCC is connected in series from the square pad -> 10k resistor, pin30 -> pin10, C1 (0.1uf) -> C2 (0.1uF) The square pad (for VCC) is outside the drawing board to the left. I was certain that these are supposed to be connected in parallel. I apologize if I am missing something here but I do not see any thing wrong with my schematic. Please correct me.enter image description here

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  • \$\begingroup\$ I'm not sure what you mean about connecting things in series and parallel. Branches of a circuit can be in series or parallel. But individual pins aren't in series or in parallel. They're just connected to whatever they're connected to. \$\endgroup\$
    – The Photon
    Commented Oct 11, 2016 at 1:37
  • \$\begingroup\$ Please get rid of the angled wires. They make things more confusing and just look ugly. Stick to 90 degree wire angles in the schematic \$\endgroup\$
    – DerStrom8
    Commented Oct 11, 2016 at 1:44
  • \$\begingroup\$ Also, make sure the pad size you need/want is right. They look a little big for me... \$\endgroup\$ Commented Oct 11, 2016 at 22:09

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All the pins in your schematic that are connected to the same named net need to end up connected to each other in the layout. For example, the IC's pin 10, the mounting pad, and the one pin of the 10 kohm resistor need to all end up connected to each other.

The ratsnest lines (or whatever Eagle calls them) don't mean you have to connect from IC pin 10 to the pad to the resistor. If you connect from the IC directly to the resistor, Eagle will sort it out and remove one ratsnest line. And probably re-adjust the remaining one to be as short as possible and still indicate the required connection.

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  • \$\begingroup\$ "For example, the IC's pin 10, the mounting pad, and the one pin of the 10 kohm resistor need to all end up connected to each other" If this is the case then aren't they connected in series? Does this mean my circuit schematic is okay? \$\endgroup\$
    – steven
    Commented Oct 11, 2016 at 2:06
  • \$\begingroup\$ No, they aren't in series. Current from the IC doesn't have to go through the resistor to get to the pad, for example. \$\endgroup\$
    – The Photon
    Commented Oct 11, 2016 at 2:07
  • \$\begingroup\$ But it looks like it does from the board layout. Oh man I am so confused \$\endgroup\$
    – steven
    Commented Oct 11, 2016 at 2:07
  • \$\begingroup\$ How so? The IC pin 10 has a direct connection to the pad, and a direct connection to the resistor. The other end of the resistor is connected to different stuff. \$\endgroup\$
    – The Photon
    Commented Oct 11, 2016 at 2:08
  • \$\begingroup\$ The direct connection must mean that the voltage is divided among pin 10 and the resistor right? Shouldn't the line connecting pin 10 and the pad have one more branch connecting to pin30? \$\endgroup\$
    – steven
    Commented Oct 11, 2016 at 2:09
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The square pad outside the drawing is NOT VCC, it is reset! VCC is the pad at the bottom of the drawing!Ground is the left hand pad of that cluster of three at the top...

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