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I Have the following Schematic:

Schematic of Two batteries

The book i am using ask for \$V_{BC}\$ which I found by \$V(B) - V(C) = 0V - 9V = -9V\$

The book gives the answer as 9V, is it safe to assume that since voltage is similar to pressure, we cant have negative pressure so I can take the modulus of my result and it would be equal to the 9V would this be allowed ?

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  • \$\begingroup\$ Voltage is only a little similar to pressure. You need to understand what it is, including how does voltage behave with conductors, voltage sources and isolators. \$\endgroup\$
    – user76844
    Oct 17, 2016 at 17:48
  • \$\begingroup\$ Use V(final) - V(initial), in this case V(C) - V(B). It is very common to make sign mistakes when doing circuit analysis. Be careful. \$\endgroup\$
    – klamb
    Oct 17, 2016 at 17:49
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    \$\begingroup\$ @EugeneSh., then why do we call the base-emitter voltage of an BJT \$v_{be}\$ instead of \$v_{eb}\$? I've always seen the convention that \$v_{ab} = v_a - v_b\$. I think OP's book just has a typo or error in its solution. \$\endgroup\$
    – The Photon
    Oct 17, 2016 at 18:04
  • \$\begingroup\$ @ThePhoton Hm. Looks like you are right and I am too rusty at this theory... \$\endgroup\$
    – Eugene Sh.
    Oct 17, 2016 at 18:06
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    \$\begingroup\$ The convention definitely is \$V_{AB}=V_A-V_B\$, and the book is wrong. \$\endgroup\$ Oct 17, 2016 at 18:27

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