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Each phase contains three loads in parallel: -j100, 100 and 50+50j ohm.b Assume positive phase sequence with Vab = 400 /__0 V Find Van and IaA and total power drawn by load.
I found line voltage as
$$Vline=Vphasor∗sqrt3=231volts.$$
But I can't get the correct value of Ian and power. I tried
$$Ian=Van/Zphasor$$
by putting
Van= 231/__-30°
and calculating
Zphasor= sum of all impedances Zphasor=-j50+150= 158/-18.4 but I cant get correct answer for Ian. Correct answers are: 4.62/-30° and 3200 W.
You got the phase voltage right.
The equivalent parallel of the three impedances is:
\$Z_{eq} = \frac{1}{\frac{1}{-100j}+\frac{1}{100}+\frac{1}{50+50j}} = 50 \Omega\$.
The current can be calculated using:
\$I=\frac{V}{Z}=\frac{230.94/-30°}{50}=4.6188/-30° A\$
And total three-phase power (three times single-phase power):
\$S = 3 V_{ph}I^{*} = 3 (230.94/-30°)(4.6188/+30°) = 3200 W\$
