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I need to apply a current in the body by two electrodes and then analyze this signal, I will receive the signal by other 2 electrodes and amplify using a instrumentation amplifier using three Op Amps (TL084CN). But, I can not to simulate the offset by voltage controlled current source in a instrumentation amplifier.

I am using the topology described in the article "Design of an Instrumentation Amplifier - Justin Bauer", where the gain is 10. Example: With Vin = 500mV peak to peak, then Vout = 5V peak to peak. (Gain = 10). Putting 5V DC on Vref, then Vout is oscillating between + 10V and 0V. All right.

My problem is: Using a current source (Mirrored Modified Howland Current Source (MMHCS)) where +Iout = 1mA and -Iout = -1mA. With a initial voltage source where amplitude = 2V and the frequency = 1kHz. I can not to simulate the offset. Vout is always between + 10.5V and -10.5V. enter image description here I tried to apply in Vref 10V, 5V, 2V, but nothing works. The Vout still varies from -10.5V to + 10.5V. The Vref only distorts the voltage signal. I want the Vout varies between (say) + 20V and 0V, it will use the AD converter Arduino Uno, that just read positive signs. I am using Proteus 8.5.

What am I doing wrong?

Sorry my poor english, i don't speak english.

Bibliography:

http://www.egr.msu.edu/classes/ece480/capstone/spring15/group05/uploads/4/7/5/1/47515639/ece_480_app_note_justin_bauer.pdf

https://www.researchgate.net/publication/258327515_High_Accurate_Howland_Current_Source_Output_Constraints_Analysis

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  • \$\begingroup\$ what resistance are you modelling for the body. \$\endgroup\$ – Andy aka Oct 30 '16 at 17:43
  • \$\begingroup\$ I think you don't need two current sources, just one will do. Electrode 2 should be connected to ground. Also, the human body is an antenna for RF signals, so you should have input filters on Electrodes 3 and 4. There could also be DC offsets caused by differing skin-electrode electrolytic potentials, so I would AC-couple the amplifier inputs (unless you want to measure these DC offsets too!). \$\endgroup\$ – Rich S Oct 30 '16 at 17:45
  • \$\begingroup\$ The amplifier's gain-setting resistor, R7, will probably need to be adjusted in real-world use, to keep the output signal within the range of your power supplies. This is usually done by replacing R7 with a digipot (digital potentiometer). The digipot is controlled by your computer device (Arduino, etc.). \$\endgroup\$ – Rich S Oct 30 '16 at 17:50
  • \$\begingroup\$ I'm not modeling any resistance to the body. I'm connecting the current source outputs directly to the instrumentation amplifier inputs. As if the body had no resistance. \$\endgroup\$ – Dyarlen Oct 30 '16 at 19:39
  • \$\begingroup\$ That makes no sense. Those inputs have giaohm impedences \$\endgroup\$ – Scott Seidman Oct 30 '16 at 22:29
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I'm not modeling any resistance to the body. I'm connecting the current source outputs directly to the instrumentation amplifier inputs.

That looks like the problem - you are trying to inject a mA into a giga ohm (the input impedance of the InAmp) and not surprisingly the current driver cannot force 1 mA into 1 Gohm. It would be able to if the power rails were +/- 1 million volts but they aren't and cannot be.

Try putting 100 ohm across the output of the two drivers. This then forces a voltage of 100 mV and, with a gain of ten you will get 1V out. Your expectations of 20V out are unreasonable given that the InAmp power rail is 12 volt.

One more thing - you will need a galvanic connection between the driver circuit 0 V and the InAmp 0 V. The human body (a real one) might facilitate this via other "connections" but for your simulation you'll need one.

Try 100 kohm.

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  • \$\begingroup\$ Thanks for the help, i will research about galvanic isolation. \$\endgroup\$ – Dyarlen Oct 31 '16 at 1:11

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