Here is the circuit:
I have to find maximum average power. By $$Pmax= |Vth|^2 /8 Rth $$ For that I need load impedence Z
I correctly found it as,
$$ Z= (j10- j4 + 8)|| 5 =3.421 + j 0.737$$
But I'm unable figure out How to find Vth?
Is this solution correct: open circuit the capacitor then the left side of circuit Is at 8*2=16 Volts . We have to find Vth so by voltage division Vth=16 (5/5+j10)