After reading this answer, I got to know that battery lasts about Total charge divided by current draw.
So, lets assume the voltage across 2 terminals of battery is constant. by, $$ V(Constant) = IR$$
If I apply high resistance load in series, then very low current will flow and the battery will be drained even more slowly.
My question is, Is my understanding correct(or I am missing something)?
(I have never made any circuit other than led in series,parallel)I was going to use LDR to turn on and off led lights. Earlier i used to think that high resistance produces heat$$H=I^2Rt$$ and that would consume a lot of energy wasted in heating. so battery will be drained faster. But today i read that above linked post and my concepts changed.
(I don't know whether this question was asked before. because I don't know how do I search for it. I searched battery and resistance but irrevelant results came. so I asked question)