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Question: Are these two circuit equivelent (the same)?

Is this the same as enter image description here

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    \$\begingroup\$ Answer: What do you think, and why? \$\endgroup\$ Nov 18, 2016 at 9:37
  • \$\begingroup\$ @TomCarpenter I think so: because L2 and C2 are both connected to the +terminal of L3 (the top side) \$\endgroup\$ Nov 18, 2016 at 9:38
  • \$\begingroup\$ If you are planning on taking an output from a node on this circuit then no, they are not the same. \$\endgroup\$
    – Andy aka
    Nov 18, 2016 at 9:41
  • \$\begingroup\$ @Andyaka When I want to find the current from the source I can use it? \$\endgroup\$ Nov 18, 2016 at 9:43

1 Answer 1

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Look good and you see that only C3 and L3 have changed position. Connecting wires do not change a circuit. Now if you need to calculate voltages and currents in such a system then all loop currents are the same in both diagrams. If we take the -V as reference then the voltage and phase at the node between C3 and L3 is different depending on the values of C3 and L3.

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