Question: Are these two circuit equivelent (the same)?

Is this the same as enter image description here

  • 1
    \$\begingroup\$ Answer: What do you think, and why? \$\endgroup\$ Nov 18 '16 at 9:37
  • \$\begingroup\$ @TomCarpenter I think so: because L2 and C2 are both connected to the +terminal of L3 (the top side) \$\endgroup\$ Nov 18 '16 at 9:38
  • \$\begingroup\$ If you are planning on taking an output from a node on this circuit then no, they are not the same. \$\endgroup\$
    – Andy aka
    Nov 18 '16 at 9:41
  • \$\begingroup\$ @Andyaka When I want to find the current from the source I can use it? \$\endgroup\$ Nov 18 '16 at 9:43

Look good and you see that only C3 and L3 have changed position. Connecting wires do not change a circuit. Now if you need to calculate voltages and currents in such a system then all loop currents are the same in both diagrams. If we take the -V as reference then the voltage and phase at the node between C3 and L3 is different depending on the values of C3 and L3.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.