I'm a complete beginner to electrical engineering, so I think I might be doing something stupid here. I have a set of grill temperature probes I ordered from Amazon. I am trying to find out the resistance of these probes using this tutorial from adafruit.

I don't want to cut the connector off of the end, so I am trying to measure the resistance of the probes by clipping alligator clips between the two sections of the connector and my multimeter probes.

No matter what Ohm range I have my multimeter set to (600, 6k, 60k, 600k, etc.), it only ever displays "0.L". Am I doing something wrong?

Multimeter in 60KOhms range reading "0.L" Connection testleads => crocoplugs Connection crocoplugs => thermometer

  • 4
    \$\begingroup\$ They are thermocouples, not thermistors. You need a thermocouple driver chip, such as the MAX31855. Make sure you get the same flavour of chip as you have thermocouple (K, J, etc). \$\endgroup\$
    – Majenko
    Nov 19, 2016 at 17:14
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    \$\begingroup\$ Switching your DMM to °C/°F mode may yield results. \$\endgroup\$
    – Majenko
    Nov 19, 2016 at 17:16
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    \$\begingroup\$ Aha! Thank you, @Majenko, switching to ºC/ºF gave me a good result. So I was wondering if this was actually a thermocouple, but almost everything I read online said that a replacement food temperature probe like this is just a thermistor. So, for future reference, how do I know if I'm dealing with a thermistor or a thermocouple? \$\endgroup\$
    – LGFaler
    Nov 19, 2016 at 17:40
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    \$\begingroup\$ By reading what it says when you buy it. Also buy from somewhere that actually tells you what it is you are buying. \$\endgroup\$
    – Majenko
    Nov 19, 2016 at 17:42
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    \$\begingroup\$ Thermocouple is a dead short. So that does not explain overload reading. \$\endgroup\$
    – user57037
    Jun 25, 2017 at 20:52

2 Answers 2


Your meter's "ºC/ºF" setting requires a K-type thermocouple which is sold as an accessory. Connecting your meter's "voltage" probes through alligator clips to the temperature probe likely produced one or more thermocouple junctions (Seebeck effect), and it could very well be that you "got lucky" in that your meter is responding to these junctions and not to the temperature probe itself. You might be able to verify this by removing the temperature probe, connecting the two alligator clips together, wrapping your hand (a heat source) around ONE of (not both of) the 'X' junctions shown in Fig. 1 below, and observing whether the meter still indicates a temperature reading (anything at all) when the "ºC/ºF" mode is selected:

DMM+ ---probe-->X<--alligator--\
DMM- ---probe-->X<--alligator--/

Figure 1

As @Whit3rd mentions, there are many types of devices that can measure temperature. Resistance Temperature Detectors (RTD) are also commonly used as oven/grill temperature sensing elements. When measured with an ohmmeter, a two-terminal RTD usually measures somewhere from tens of ohms to tens-of-thousands of ohms, depending on the probe's construction. For a probe the size of the one in picture you provided, the wire(s) that comprise the RTD's temperature sensing element could be very thin.


Some ohmmeters, when set to their low-ohms measurement range(s), can output substantial current. If an RTD is constructed from a very thin wire, that wire could potentially fail open circuit (like a fuse link that heats up and eventually melts or "blows") if too much current passes through the wire. If the wire fails open, that would explain the "O.L" overload indication you're seeing when measuring the probe's resistance.

And as others have already said, a thermocouple is basically two dissimilar metals that are bonded together at one end, with a temperature gradient across them. A two-wire (low precision) resistance measurement made with a handheld DMM across a thermocouple junction should indicate a "dead short" (~0 ohms). You're not measuring a dead short you're measuring open circuit ("O.L" overload): so either a) your temperature probe is not a thermocouple (it's an RTD, or a diode type, or whatever), or b) it is a thermocouple but it is damaged (failed open circuit). FWIW, thermocouples are typically very robust. One typically wouldn't damage a thermocouple by measuring its resistance with an ohmmeter--even one that outputs relatively high current on the low-ohms ranges; so I'm betting against option b) here.


First verify if your alligator clips actually conduct electrical current by connecting them together and see if you get a low reading. This is the crucial first step on any resistance measurement.

If that was the case, and you still get an overrange indication, then try reversing your terminals of your meter (and/or switch your meter to diode testing) while connecting to your probe. If reversing does result in an actual measurement instead of overrange, you're dealing with an diode, not a thermistor.

  • \$\begingroup\$ ...or it could be a thermocouple. \$\endgroup\$
    – Bort
    May 24, 2017 at 17:55
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    \$\begingroup\$ Thermocouple is a dead short. It would not read overload if it was a thermocouple. \$\endgroup\$
    – user57037
    Jun 25, 2017 at 20:53

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