You are getting current amplification. Ib to Ie is getting amplified: 0.15mA -> 6.5mA. That's a current gain of ~43X.
The output of the battery has to account for all of this current so that's why it's greater than Ie. A little bit of current from the battery flows through the 10K resistor which is why the battery current shows more current than any other point.
To be clear, a transistor amplifies current between its nodes. It cannot make a battery source more current than the battery will output on its own. The exception to this is if you have a boost converter or a circuit that isn't just aimed at regulating current.