I'll try and keep this simple: -
- With RL equal to 100 kohm and C2 equal to 100 nF you create a low pass filter with cut-off frequency equal to 159 Hz.
- At 1.59 kHz the attenuation is 20 dB and at 15.9 kHz the attenuation is 40 dB (i.e. rising at 20 dB per decade in frequency).
- At 159 kHz, attenuation will be 60 dB and at 1.59 MHz attenuation will be 80 dB.
So at 2 MHz, the attenuation will be a bit more than 80 dB - how can you expect this circuit to oscillate when the gain (formed by RF and R1) is only ten? Think about what you are doing here.
But it gets worse because, for series resonance (that's what this design is attempting to emulate), there is a further level of attenuation caused by CS and C1. Both CS and C1 form the capacitive branch of a tuned series circuit but given that CS is only 0.0122pF and C1 is 10 nF, there is a further attenuation of 820,000 or 118 dB at C1.
Hopefully you should realize now that RL, C1 and C2 are totally inappropriate values. If, as you say in a comment, that your book gave these values you should either buy some reading glasses or throw away the book.
Can anyone guide me what functions should I choose for the voltage
The only voltage sources I can see are the DC supplies to the LT1001 and, at 15 volts these seem adequate but, now that we are discussing the op-amp, take a look at the data sheet and you will see that it has a gain-bandwidth product (GBP) of typically 0.8 MHz. This means that the op-amp runs out of steam and is unable to provide voltage amplification at a frequency greater than 800 kHz.
In other words, the op-amp is totally unsuited for operation as a Pierce oscillator at 2 MHz.
So, choose an op-amp with a GBP greater than (say) 50 MHz, make RL more like 100 ohms (not 100 kohms), and make C1 and C2 more like 10 pF (pico farads) and it might just work.