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Does a Y to delta transform for resistors work the same way when inductors a connected in a similar fashion?

schematic

simulate this circuit – Schematic created using CircuitLab

I have a load bank that is wired in a Y configuration. I'm given the specks for loading in a delta configuration. I'm trying to figure out if these loads will work.

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Y to Δ conversion formula remains the same for all impedances (\$Z\$). In case the impedance is just a resistor, replace \$Z\$ with \$R\$. In the case of an inductor, replace with \$Z=j L \omega\$. In the case of a capacitor, it must be \$Z=1/(j C \omega)\$. In case of combinations of these elements, add them and replace \$Z\$.

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Does a Y to delta transform for resistors work the same way when inductors a connected in a similar fashion?

yes. Absolutely identical. Same applies to capacitors, or any general complex impedance element.

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