# Y to Delta transform with inductors?

Does a Y to delta transform for resistors work the same way when inductors a connected in a similar fashion?

simulate this circuit – Schematic created using CircuitLab

I have a load bank that is wired in a Y configuration. I'm given the specks for loading in a delta configuration. I'm trying to figure out if these loads will work.

Y to Δ conversion formula remains the same for all impedances ($Z$). In case the impedance is just a resistor, replace $Z$ with $R$. In the case of an inductor, replace with $Z=j L \omega$. In the case of a capacitor, it must be $Z=1/(j C \omega)$. In case of combinations of these elements, add them and replace $Z$.