I'm going to use 1S Li-po, 3.7V. ESP8266 needs 3.3V and it takes 350mA peak on startup. When running it needs about 70mA.

The ESP task is to wake up, measure, connect to wifi and post data to server. It will wake up every 2 hours. I'm wondering which regulator is better for low power modules, LDO or switching. I know that LDO efficiency is a lot less efficient but they have lower quiescent current. On the other hand the switching offers better efficiency. Which one I should use?

  • \$\begingroup\$ Well, what requirements do you have for a regulator? \$\endgroup\$
    – PlasmaHH
    Commented Dec 1, 2016 at 20:21
  • 3
    \$\begingroup\$ "I know that LDO efficiency is a lot less efficient" - No it isn't. Dropping 3.7V to 3.3V with a linear regulator is 3.3/3.7 = 89% efficient. Decent buck converters are in the same ballpark, cheap crappy ones are probably significantly worse. A good buck converter designed for these exact specs could maybe reach 95%; probably not worth the hassle over a linear regulator imho. I would, however, worry about the minimum voltage drop over the linear regulator; pick yours carefully. edit: I should read more carefully; Li-Po source. Its voltage may be over or under 3.7V, changing things... \$\endgroup\$
    – marcelm
    Commented Dec 1, 2016 at 20:25
  • \$\begingroup\$ Continuing this; you probably will need a switcher, not because of efficiency but because the battery voltage range is too diverse for the ESP. See this related question (in fact, this might be a duplicate). \$\endgroup\$
    – marcelm
    Commented Dec 1, 2016 at 20:35
  • \$\begingroup\$ @PlasmaHH Li-po battery, so Vin 3.7-4.2V, Vout 3.3V, I'm not sure about Iout, ESP needs some time to boot up and it needs 350mA (maybe I can fit into Ipeak). I'll measure this time tomorrow. As I mentioned earlier 70mA when running. Eficiency as high as possible, quiescent current as low as possible \$\endgroup\$
    – KaDw
    Commented Dec 1, 2016 at 20:38
  • 1
    \$\begingroup\$ Can the regulator be duty cycled along with the communications module? You can easily find a dc-dc converter that will run less than 1uA in a shutdown mode. If you have i.e. a micro running directly off the battery which is responsible for waking up the wifi module, just have it shut down and wake up the regulator along with it... \$\endgroup\$
    – user49628
    Commented Dec 1, 2016 at 21:56

2 Answers 2


Good discussion already. I'll summarize the linear option as an answer.

  • A datasheet for the ESP8266 says that it can tolerate from \$3.0\:\textrm{V}\$ to \$3.6\:\textrm{V}\$.
  • A 1S Li-Po starts out almost \$4.2\:\textrm{V}\$ with low load and is nearly empty by about \$3.4\:\textrm{V}\$.

That leaves only about \$100\:\textrm{mV}\$ of headroom towards the end of battery life and that's probably not enough. It's almost certain that you'll need at least twice that much, using an LDO at \$70\:\textrm{mA}\$ and perhaps three times it at the initial \$350\:\textrm{mA}\$ you mentioned.

But it still may be possible to consider using a linear regulator, if you choose to operate at a lower voltage. One that is at or below \$3.1\:\textrm{V}\$. Sure. That's not much wiggle room. But at least it's non-zero. Still, you may also have to consider what else surrounds the ESP8266, too. And you've asserted the need for \$3.3\:\textrm{V}\$ but you haven't disclosed whether or not perhaps \$3.0\:\textrm{V}\$ or \$3.1\:\textrm{V}\$ could be successful. (Okay. I don't know of a fixed \$3.1\:\textrm{V}\$ linear LDO with low quiescent current. So probably \$3.0\:\textrm{V}\$.)

Given all of the above, all I can suggest regarding a linear LDO option is something like the LT1763. It may meet your needs. It's quiescent current is about \$30\:\mu\textrm{A}\$, too, and requires at most \$300\:\textrm{mV}\$ of overhead for your case. So perhaps.

Given a short search (you really should do your own), I did find this from TI: TPS783xx. The spec is below your peak startup current, but well above your operating current. And the quiescent current is extremely low, I believe.

  • \$\begingroup\$ I'm searching though mouser for LDO with lower quiescent current. Do you know any? \$\endgroup\$
    – KaDw
    Commented Dec 1, 2016 at 21:10
  • \$\begingroup\$ @KRol No, not offhand. That's usually considered "low" and, in fact, it's called out right at the top of the datasheet as an ad. And in the text they call forth "Quiescent current is well controlled; it does not rise in dropout as it does with many other regulators." It is, however, very temperature dependent (so they haven't attempted a Wyatt topology, I suppose.) At the active currents you are talking about, I don't normally expect better. But here's one: ti.com/lit/ds/symlink/tps783.pdf \$\endgroup\$
    – jonk
    Commented Dec 1, 2016 at 21:42
  • \$\begingroup\$ With 'requires at most 300mV of overhead for your case' you mean that it's dropout voltage is 300 mV at most, right? Regarding headroom, besides LDO's being available with lower V_dropout, at V_In=3.4V the battery is probably quite empty anyways and it's perhaps advisable to stop discharging it for longer battery life. But say you want to discharge it to 10 % remaining capacity or so and for that you enter the dropout zone a little bit for a short time - would that be so bad? I mean since the EPS8266 is tolerant to voltages slightly below 3V ... \$\endgroup\$ Commented Mar 13, 2022 at 12:47

There are several LDOs available with quite low quiescent current (I_Q) in the single digit micro ampere range.

For example, the Microchip MCP1700-3302E LDO just has typical I_Q of 1.6 µF, V_In range of 2.3..6V (which is sufficient for your use case), low dropout voltage (178 mV typ, 350 mV max) and provides output current up to 250 mA.

This is less than the 350 mA peaks you mention during startup, but the datasheets specifies:

For some applications, there are pulsed load current events that may exceed the specified 250 mA maximum specification of the MCP1700. The internal current limit of the MCP1700 will prevent high peak load demands from causing non-recoverable damage. The 250 mA rating is a maximum average continuous rating. As long as the average current does not exceed 250 mA, pulsed higher load currents can be applied to the MCP1700. The typical current limit for the MCP1700 is 550 mA (TA + 25°C).

(Section 6.5 Pulsed Load Applications, emphasis mine)

However, I don't know if the ESP8266 peaks are short enough to qualify as such a permissible pulsed load.

You are on the safe side with the Richtek RT9080 LDO which is rated for I_out=600mA, has typical I_Q=2µA and V_drop=125mV at I_out=250mA.

However, it doesn't really matter that much if your LDO has an I_Q of 2 µA, 1 µA or 0.5 µA since its efficiency is dominated by the V_In/V_Out voltage difference.


enter image description here

So if you use an LDO your efficiency changes from 78 % (at V_In=4.2V) to 89 % (at V_In=3.7V) while you battery discharges.

However, the majority of the battery lifetime V_In equals 3.7V, where the 89 % efficiency value is indeed quite good.

In contrast, a buck converter is more efficient over a greater range. For example, the Texas Instruments LM3671 has efficiency of 90 % or so for your active input/output voltages/currents (with I_Q_typ=16 µA and I_Q_max=35µA):

enter image description here

(LM3671 datasheet, page 9)

So it's more efficient in the beginning when your battery is fully charged, it's perhaps a little bit more efficient during startup of your ESP8266 but it has basically the same efficiency as an LDO most of the time when I_out=70mA and V_In=3.7V. Also, your ESP8266 is sleeping most of the time, where it consume 0.1 mA or so, and there the LM3671 is basically as efficient or even less efficient as an LDO (between 67 and 75 % or so).

So it's really close. You could try to build a very precise model that includes the duty times of your different activity modes and the self-discharge characteristics of your battery to see whether the LDO or buck saves you a few days of runtime - or not. Probably, it isn't worth it.

Other pro/cons:

  • the mentioned LDOs are much cheaper than a buck converter
  • an LDO is simpler to integrate (i.e. it just requires 2 decoupling capacitors whereas a bucket requires some more extra parts)
  • the MCP1700 is widely available also as through-hole part (-> easier to solder/bread-board)
  • since a buck converter is switching it's a noise source

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