# How to calculate baud rate and determine the number of stop bits in asynchronous serial

Below is the given question:

For my understanding, 1/baud_rate = 104.16 However, when I tried to do reverse division, the result is so different than expected.

1. My calculation to find baud rate: 1/104.16 =9.6006 * 10^-3

Is my calculation of baud rate wrong?

2.How do I determine the number of stop bits in this case?

• The link just provides some dark blue background page, without it I have no idea what you are asking. – PlasmaHH Dec 8 '16 at 15:51
• Any receiver can handle the specified number of stop bits or arbitrarily more. Almost all modern UARTS only need one stop bit on receive. Sending out 2 is occasionally used to pace data but is a RARE need after the days of Teletype terminals, paper tapes punches and primitive protocol converters. – KalleMP Dec 8 '16 at 19:17

Baud rate is $\dfrac{1}{104.16\times 10^{-6}}$ = 9600.6 bits per second.