Other than the obvious eating them, is it possible to squeeze enough electricity out of a coin cell battery to cause harm? Maybe using a boost converter with a large capacitor? Or maybe using a bunch of them in series?

  • \$\begingroup\$ With one cell: probably yes but the chance of actually killing someone with only the energy from one coin cell is quite low I think. The famous electric chair uses more power but still most victims aren't killed instantly. Coin cells are not good at delivering a large amount of energy in a short time. Which is what would be needed. Not seeing the point of this question though. \$\endgroup\$ Dec 23, 2016 at 7:09
  • \$\begingroup\$ Related: youtu.be/8hwLHdBTQ7s \$\endgroup\$
    – winny
    Dec 23, 2016 at 7:22
  • \$\begingroup\$ They can be fatal if swallowed. \$\endgroup\$
    – pjc50
    Dec 23, 2016 at 7:58
  • \$\begingroup\$ @pjc50 The OP already called that out in the first clause. \$\endgroup\$
    – jonk
    Dec 23, 2016 at 8:00
  • 1
    \$\begingroup\$ @ChrisH Propulse them with a coilgun then ! \$\endgroup\$
    – zakinster
    Dec 23, 2016 at 14:16

3 Answers 3


A CR2032 holds about 2400 useful Joules of energy. Operating entirely within specification, it can supply \$200\:\mu\textrm{A}\$.

If applied subcutaneously, \$10\:\mu\textrm{A}\$ can be sufficient to cause fibrillation. So if you could apply the battery directly near the heart and underneath the skin, I suppose it could directly kill someone without any additional circuitry.

From an editorial in Anesthesia & Analgesia, June 2010, Volume 110, Number 6, International Anesthesia Research Society, pp 1517-1518, "Electrical Safety in the Operating Room: Dry Versus Wet," by Steven J. Barker, PhD, MD, and D. John Doyle, MD, PhD, FRCPC, the following quote is found:

Microshock refers to very small currents (as little as \$10–50\:\mu\textrm{A}\$) and applies only to the electrically susceptible patient, such as an individual who has an internal conduit that is in direct contact with the heart. This conduit can be a pacing wire or a saline-filled central venous or pulmonary artery catheter. In the electrically susceptible patient, even minute amounts of current (\$10\:\mu\textrm{A}\$) may cause ventricular fibrillation.

(The above information was pointed out in a comment here by Russell McMahon and is a substantial improvement over citing a Wiki page.)

I've read that death can be caused with as little as 50 Joules. But I think 100 Joules is a more certain estimate. Lethality (with AC, anyway) is pretty common even at \$200\:\textrm{V}\$. So if I had to make an educated guess, I'd probably guess that using a Sanyo OS-CON Aluminum-Polymer (way too expensive and you'd need lots of them) or aluminum capacitor (such as Vishay BCcomponents' Aluminum Electrolytics), with \$200\:\textrm{V}\$ and 100 Joules would be sufficient. This suggests a value of \$5\:\textrm{mF}\$.

However, it would take a while to achieve. Assume you can design a circuit that is, overall, 50% efficient in charging this capacitor from a single CR2032 while staying fully within specs and drawing just \$200\:\mu\textrm{A}\$ from it. Then on first blush it would take 10000 seconds or about \$2\:\frac{3}{4}\$ hours to charge it up for one such use if you could sustain \$200\:\mu\textrm{A}\$ throughout the process. But the CR2032 is only capable of sustaining about \$600\: \frac{\mu\textrm{J}}{\textrm{s}}\$ of power. So really, I think this would take closer to four days to achieve. (And that doesn't account for capacitor leakage. With the Vishay capacitor mentioned above, leakage power may be below charging power near the end, but it probably will add a fair bit more time to the process.)

So the answer is probably "technically, yes" but rather unlikely as it would be quite odd to open someone up in order to stick a button battery across some tissues inside their body near the heart (read: very low probability) and it is similarly unusual to find a circuit designed to charge up a large, low ESR capacitor from a battery supplying just \$600\:\mu\textrm{W}\$ continuous and requiring almost a week to charge up (read: low probability.)

Of course, now that someone is thinking this way, I am sure such a circuit will be promptly designed and then sold as pet rocks to millions of happy consumers, making this a significant problem in the wild. ;)

  • \$\begingroup\$ I believe OP means something like get a high-voltage oil-filled industrial capacitor, and make a voltage multiplier out of the coin, and charge it to 10kV. But these caps can kill you even without any coin if left unattended without crowbar short. \$\endgroup\$ Dec 23, 2016 at 8:08
  • \$\begingroup\$ @AliChen Hmm. I'd read it as wondering about a boost circuit for any sufficiently high voltage. Not necessarily 10 kV. \$\endgroup\$
    – jonk
    Dec 23, 2016 at 8:11
  • \$\begingroup\$ Also, coin cells are routinely used in cheap magnifiers with LEDs, so it is not unheard of having ~10mA from a CR2032 coin. So it should charge a 10uF cap to 3kV in about 1 hour. \$\endgroup\$ Dec 23, 2016 at 8:37
  • 3
    \$\begingroup\$ If you open someone's chest and put a lump of metal in the heart, it really doesn't need to be a battery ;) \$\endgroup\$
    – Mołot
    Dec 23, 2016 at 12:16
  • 1
    \$\begingroup\$ @Mołot +1 just for making me laugh :D \$\endgroup\$
    – Daffy
    Dec 24, 2016 at 9:02

The simple answers are:
1) Very unlikely to be killed or greatly harmed, with only one cell.
2) Very certain to be killed or greatly harmed, with enough of them!


A long sharp steel wire in a wood handle, shoved between ribs into heart, it might work much better if using two sharpened wires, with coin-cell attached between!


2400 joules in an energy-storage oil capacitor at about 3KV will explode flesh like a bomb. (That's the quarter-shrinker capacitor used in room-freshener mode, where it explodes a single cherry into fine mist. Very, very loud. Smells nice.) Hydrostatic shock reflecting around within the body may tear up blood vessels and brain tissue. http://amasci.com/amateur/capexpt.html


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