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For t > 0 find v0(t)

enter image description here

Using nodal analysis I was found v1 and v2, take difference and find correct result

But I can’t make same with direct KCL, KVL approach

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May anyone help with that?

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  • \$\begingroup\$ That was fixed but result still incorrect \$\endgroup\$
    – MaxMil
    Commented Dec 29, 2016 at 9:00
  • \$\begingroup\$ Is \$8(e^{-t}-e^{-6t})\$ incorrect? \$\endgroup\$
    – Chu
    Commented Dec 29, 2016 at 9:09
  • \$\begingroup\$ That is correct! But my in MathCAD "v0(s) invlaplace -> ..." is not equal to your calculations, but why? \$\endgroup\$
    – MaxMil
    Commented Dec 29, 2016 at 9:14
  • \$\begingroup\$ Ask MathCAD!!!!! \$\endgroup\$
    – Chu
    Commented Dec 29, 2016 at 9:15
  • \$\begingroup\$ Are you find result handy? \$\endgroup\$
    – MaxMil
    Commented Dec 29, 2016 at 9:16

1 Answer 1

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Your equation for \$V_o(s)\$ may be factorised to: $$\frac{40}{(s+1)(s+6)}=\frac{8}{s+1}-\frac{8}{s+6}$$

Giving: $$v_o(t)=8(e^{-t}-e^{-6t})$$

The MathCAD answer is also correct (expand it by hand to see), but not in as compact/useful a form.

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