By using the open loop transfer function for a control system, how would you then sketch the Nyquist plot by hand?

I'm aware you'd substitute any \$s\$ term for \$j\omega\$ and then rationalise the denominator by moving the \$j\$ terms to the numerator. But from this point forward I am unable to get to the point where I can plot the rough shape of the Nyquist plot. Any break down of the steps would be greatly appreciated.

  • Can you draw a Bode plot by hand? – John D Jan 19 '17 at 23:15
  • Yes i can for certain systems, control is quite a new topic for me which i'm studying in my final year of engineering. I need to be able to plot Nyquist plots for an exam next week and i'm struggling to get my head round them – jackthompson Jan 19 '17 at 23:17
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    So assuming you draw the Bode plot you have gain and phase information- How would you translate that information to a Nyqvist plot? – John D Jan 19 '17 at 23:33
  • Using the bode you could get phase values for corresponding gain values and plot them on the complex plane taking the phase angle from the real axis. But we won't have access to that information to sketch the plot we need to be able to determine quickly its general shape and where it crosses the axes and weather or not it approaches from a negative or positive quadrant – jackthompson Jan 20 '17 at 0:01
  • This sounds like a different question to what you actually asked. What it sounds like you need is to be able to quickly recognise how a given transfer function would be illustrated as using a Nyquist plot, rather than calculating each point. Perhaps you should update your question. – loudnoises Jan 30 at 8:07

A system with smooth rolloff and numerous poles will become a spiral, if plotted on a polar plot.

If you have only 90 degree phase shift, then the low-freq gain, assumed to be huge, starts far out from the center point (the gain-is-zero point), rotates over to the 90 degree region and plunges down to ZERO. There is no stability issue here.

The classic purpose of Nyquist is to examine how this polar plot behaves near the [Mag=1/Phase=-180 degree] point. For stability, perhaps marginal and ringy but stable, the plot needs to be inside the magnitude=1 point at 180 degrees.

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