# Simple Node Analysis - Is the given answer wrong?

I'm doing some homework sheets, and I just wanted to know if the given answer to this problems is wrong:

I'm getting V0 (the node) as 144v and the current ia as 48A, I just wanted to confirm if the error is in the question, or if it was me who went wrong:

Here is my working out: $$\frac{6I_a-V_0}{3} = I_a$$ $$I_a = \frac{V_0}{3}$$ Then doing KCL at node V0, treating the node below the 24ohm resistor as ground, and subbing in Ia gives:

$$\frac{V_0-60}{2} + \frac{V_0}{24} + \frac{V_0-6I_a}{3} = 0$$ $$\frac{V_0}{2} - 30 + \frac{V_0}{24} + \frac{V_0}{3} - \frac{2V_0}{3} = 0$$ $$\frac{5V_0}{24} = 30$$ And then then gives V0 as 144V and Ia as 48A.

Thanks guys!

• Please note that checking whether the solution is correct does not require solving the circuit. Just use the provided solution and check if V=IR is satisfied at every resistor. It is relatively quick to see that voltages of 60V, 48V, 36V and currents of 6A, 2A, (-)4A, 12A are self-consistent. – Ben Voigt Jan 21 '17 at 15:27