1
\$\begingroup\$

I have the following example circuit:

enter image description here

I do not understand why this lights the LED. For my main project I am building a circuit that has a button connected to an output as well as the collector of the transistor as shown in the diagram. The circuit works as expected when I put the LED on the collector instead of the emitter, but this solution will not work for my overall setup. Even a 1M Ohm resistor allows current through. Am I just using transistors wrong?

\$\endgroup\$
  • 1
    \$\begingroup\$ Draw a proper circuit and not a cartoon. \$\endgroup\$ – Andy aka Jan 23 '17 at 8:46
  • \$\begingroup\$ @Andyaka fixed. \$\endgroup\$ – Elijah Seed Arita Jan 23 '17 at 9:02
  • \$\begingroup\$ So, roughly speaking you are going to see \$I_{led}\approx \frac{5\:\textrm{V}-V_{led}-V_{BE}}{R_1}\$. You have a resistor, in series with a BJT diode, in series with an LED. And you have enough voltage present to overcome the diode drops. So current flows. No surprise. Why can't you put the LED into the collector leg? \$\endgroup\$ – jonk Jan 23 '17 at 9:10
  • \$\begingroup\$ If you replace that BJT transistor with a MOSFET transistor then yea it shouldn't light up. \$\endgroup\$ – Bradman175 Jan 23 '17 at 9:49
  • \$\begingroup\$ I think I made the LED backwards \$\endgroup\$ – Elijah Seed Arita Jan 24 '17 at 2:07
0
\$\begingroup\$

enter image description here

You mean there is no supply at the collector! The emitter is the pin with the arrow however, it matters not because, you can put a meter on a transistor and find a diode between collector and base and emitter and base and this is why your LED lights.

Current from the +5 volts passes through R1, passes through the base-emitter diode and then onto the LED (which it illuminates).

\$\endgroup\$
  • \$\begingroup\$ Oops, that was supposed to say collector. I must be tired. Let me fix that. Also, yes, I see why it isn't working. I guess I will just have to redesign. I might delete this question as it doesn't provide much help for others. \$\endgroup\$ – Elijah Seed Arita Jan 23 '17 at 9:22
  • \$\begingroup\$ Don't delete the question please. \$\endgroup\$ – Andy aka Jan 23 '17 at 10:11

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.