How can I make a power supply that is able to give 4 amps in terms of current and 5 Volts fixed? I've made a power supply before with variable voltage however the amp output never went above 1A. Which materials must I implement and will it be able to run nonstop without the risk of overheating and fire?

Edit: this power supply will be used in a LED matrix with addressable chips, since this matrix is 10x10, then the total 100 LEDs will require at least 4 Amps.

Edit: This power supply will connect to the normal household electric connectors, therefore it's input will be 110v.

  • \$\begingroup\$ Since you dont provide enough info such as input voltage and working environment, I cannot suggest anything. But Webench is a nice tool to get power supply design recommendations. Another option is TOP255 and TNY268. \$\endgroup\$ – Rohat Kılıç Jan 30 '17 at 3:37
  • \$\begingroup\$ Can't you at least search for what you want on sites like element14.com, digikey or mouser? Here's a prebuilt power supply I found on element14. au.element14.com/tdk-lambda/ls35-5/… I hope you're sensible enough to know how to hook this up to the mains. \$\endgroup\$ – Bradman175 Jan 30 '17 at 4:03
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    \$\begingroup\$ From your profile it seems you are in Guatemala. Can you get laptop power supplies in Guatemala? Then you could just design a buck converter to convert 20V down to 5V @4A. Also, are you sure you want a 5V output? Or do you want a 4A output? Do your LED's want a voltage input or a current input? \$\endgroup\$ – mkeith Jan 30 '17 at 4:46
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    \$\begingroup\$ Wouldn't surplus 250W ATX PSU's be feasible? \$\endgroup\$ – Sunnyskyguy EE75 Jan 30 '17 at 5:42
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    \$\begingroup\$ You've already used a variable supply and were able to get near \$1\:\textrm{A}\$ with it. So those parts are available to you. Certainly, you can add one more TO-220 BJT and heat sink to complement your already proven variable supply made from available parts in order to boost the current compliance? (I can't imagine that being variable by itself causes you a problem. You can fix that by just not using a potentiometer and just using resistors, instead.) Am I missing something? \$\endgroup\$ – jonk Jan 30 '17 at 7:28

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