First I'd like to excuse myself for my English, especially when talking about electronics, because I don't always know the correct translations.

I plan to use this Deal Extreme portable 12 volt battery

to power my 3"5 HDD when I'm travelling.

enter image description here

However, to power a 3"5 HDD, I need 12v AND 5v at the same time. How could I achieve that ? Is the only choice using two different batteries, or would even that be a total fail, due to the mains not being the same ?

Thanks, and sorry for the mistakes

  • Note: While this answer relates to a specific question it provides general purpose advice on the operation of equipment from portable battery packs and comments on discharge rates, charge rates and capacity:

Power supplies which provide multiple output voltgaes from a single input voltage are commonly available. (For example, consider a PC power supply which makes a wide range of positive and negative voltages for a single main input, or portable versions of these, which typically use a single 12V input).

You could "easily enough" make or buy a power supply to provide 5V while also using the 12V directly.

There are portable HDDs available at reasonable cost which operate from USB and which are powered via the USB 5V supply using the USB cable. This arrangement would usually be easier and more "workable" than what you are trying to do.

What you are trying to do can certainly be achieved BUT there are a few more "fish hooks" than my be apparent.

Based on the photo below from here , the battery contains 3 x LiIon (Lithium Ion) cells connected in series (as would be expected from the stated voltage.

The voltage when fully charged will be about 12.6V and the battery at end of discharge will be about 9V (9.5V reported in mini review below). Average voltage during discharge will be about 10.5V. You need to be certain that your 3.5V HDD will run on the available voltage.

enter image description here

A user's Mini review which can be seen here says that currents above 2.5A caused the battery to "sometimes cut off output". A 3000 mAh LiIon cell is typically rated at 3000 mA max discharge, and the battery protection circuits

There are a number of other useful reviews and I recommend that you read them to see what else may be relevant.

This user says the voltage drops from 12V to 10V on a 2.5A load suggesting an internal impedance of about 1 ohm OR that a current limiter is at work.

This review says that the power adapter provides a constant 12.6V open circuit - which is correct for a 3 cell LiIon batter pack) BUT 325 mA constant current when loaded to below 12.6V. This is the rate at which the pack would be charged and would take about 7 or 8 hours to charge the pack to 80% capacity from fully discharged and probably 20+hours to fully charge the battery.

The small PCBs at the end of each battery is probably and hipefully a protection circuit.

Note that the cells are each rated at 3000 mAh. If thecells in your battery are about the same capacity as the cells in this battery then there is "summat aglae" and Deal Extreme are being very naughty in their description of the pack as a 4500 mAh battery.

Claimed weight is 268 grams, user weighing on not very good scales seen here says a bit over 200 grams.

enter image description here

  • 1
    \$\begingroup\$ Buy a USB-powered hard disk drive! \$\endgroup\$
    – spearson
    Mar 19 '12 at 23:29
  • \$\begingroup\$ There's always a choice of buck-boost converter \$\endgroup\$
    – Rok Jarc
    Mar 20 '12 at 0:17
  • \$\begingroup\$ First, this is a great answer and I'd like to thank you because I learned much. I know that buying a USB-powered HDD would be the solution, however, I have two/three reasons for not doing this : I want to improve my level in electronics. It can't be bad to hack. I'd like to have a portable 1TB HDD that I can use with my... phone (android based, with usb-host capacity), even during short durations. Now, I will follow your advice and get some more informations about those tricky batteries. I also have an idea about using an "operational amplifier" to get 5v current from 12v. Thanks, \$\endgroup\$
    – pistache
    Mar 20 '12 at 20:32

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