in the inverting buck boost the output is Vout = -Vin(d/(1-d)) , where d is the duty cycle of the switch. The output voltage is alsways negative. In my case the input voltage is provided by a battery. Is it possible to attach a load that requires a positive voltage supply simply by inverting its terminals? I'm asking this question because I can't understand why on the internet I found inverting and not-inverting buck boost converter.