1
\$\begingroup\$

I need to figure what DC power supply to choose. Requirements are:

  • after supply turned on I need to have fixed value of current of 10 A. Load in this case will be resistance ~5 mOhm. I.e. I will have small voltage of 0.05V
  • then inductive load will start creating back EMF. Back EMF magnitude could be in the range 0-30 V. BUT I still need to maintain fixed value of current of 10 A.

ALSO I may need to do the same experiment with current 100 A. Back EMF range will be the same.

I've read about constant current mode. Can anyone tell would my task fit for usually available DC power supplies with constant current mode? Any recommendation for particular models?

\$\endgroup\$
  • \$\begingroup\$ Assuming your constant current generator power source is supplying 10A or 100A through an inductor ....what event is going to create a back emf of 30 V??? \$\endgroup\$ – Jack Creasey Feb 5 '17 at 21:01
2
\$\begingroup\$

10A or 100A constant DC current to a milliohm range load is possible without heavy losses by using a switchmode circuit. The basic idea is to utilize the induction. The inductor may be your load or an extra inductor for the current regulation only.

How the inductor works: When a dc voltage is applied to a inductor its current starts to grow at rate voltage/inductance.

If the inductor has a parallel back emf suppression diode, the dc voltage can be disconnected without a spark. After the disconnection the inductor current diminishes at rate Vd/inductance. Vd means the fordward voltade drop of the diode. By switching the dc on off at high enough frequency, the current swings between two values just like the thermostat makes the temperature to swing between the upper and the lower limit. Here is the principle of the circuit:

enter image description here

Rs is the current measuring shunt (milliohms). The Osc has a schmitt-trigger that turns the fet on and off +proper high speed drive circuit for the fet. With no more in the Osc the system is a free running oscillator.

A switchmode supply control IC surely is adaptable to this for PWM control and wanted operating frequency. The free running system can be moved to higher frequency by narrowing the current hysteresis.

A milliohm range resistive load can be inserted in series with the inductor. If the inductor generates an extra emf due an external magnetic field, the +Vs must win it to keep the current. If the inductive load is an electomagnet that moves iron, high external emf pulses are expectable.

D1 must be a fast turn off and low voltade drop type and be rated for the reverse voltage Vs + the external emf. I have drawn a schottky diode just for remembering the speed and low drop.

Development ideas:

1) 100 amperes sounds high. It surely would be useful to investigate if there is available some modern switching components for high current motors.

2) the dissipation in the fet grows to enormous if there is no inductance. To be in safe some protection scheme that sees the simultaneous high fet current and voltage should be added.

3) the dissipation in D1 can be intolerably high. An active switch can have much lower fordward voltage drop. 50% smaller drop means 50% smaller dissipation. This is important because the current runs most of the time through the diode, the fet only gives a new kick when it's needed.

\$\endgroup\$
1
\$\begingroup\$

Product recommendations are off-topic here.

Your requirement of 100A at 30V implies 3kW output power, which is going to be expensive.

The current limit mode on most supplies is not really designed to operate as a constant current source (so it doesn't necessarily work all that well), also some high power supplies are switchmode and cannot go down to very low output voltage (so the 50mV output voltage might be an issue). You may be able to add some real external resistance (obviously it will have to be rated for the required power dissipation) and get around that (but the supply has to be rated for even more power to account for the lost power in the resistor).

\$\endgroup\$
  • \$\begingroup\$ To clarify: 30V is back EMF which arise due to some outside event. Power supply suppose to maintain 10 A (or 100 A) current constant by increasing output voltage to overcome reverse polarity of back EMF. \$\endgroup\$ – lowtech Feb 5 '17 at 18:50
  • \$\begingroup\$ @lowtech Okay, I'll revise. \$\endgroup\$ – Spehro Pefhany Feb 5 '17 at 18:51
  • 1
    \$\begingroup\$ Also, of course, the supply output must be rated for more than 30 volts. A 10 volt/100 amp supply will be cheaper, but probably won't survive. \$\endgroup\$ – WhatRoughBeast Feb 5 '17 at 19:29
  • \$\begingroup\$ OP may also have a problem sourcing 3kw in North America. Household receptacles can't supply that much. \$\endgroup\$ – Harper - Reinstate Monica Feb 6 '17 at 0:33

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.