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I'm trying to build an ultrasonic transmitter circuit. The datasheet specifies 20V peak-peak for the ultrasonic to operate at its maximum power. However I'm limited to only using a 9V supply. What I thought about doing is making an H-Bridge to switch the polarity of the battery between 9 and -9, giving me almost 18vpp. Do you think this is a good idea? Do you have anything else to recommend?

This is what the circuit would look like. Function generator simulates a 40kHz square wave, scope is there just to look at the output.

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  • \$\begingroup\$ Are you using a separate transducer for receiving echoes? \$\endgroup\$ – Nick Alexeev Feb 5 '17 at 21:34
  • \$\begingroup\$ Typically you would have three levels: +9V, 0V, -9V. \$\endgroup\$ – Tom Carpenter Feb 5 '17 at 23:17
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Why re-invent the wheel when you could just use the same method used by the HC SR04 using an RS232 Tx to run the sender.

enter image description here

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Ultrasonic emission sources somewhat behave and work the same way as speakers or buzzers. Using a [-Vcc to Vcc] range (with a H-Bridge) is a common practice in class D audio amplifiers to double the peak-peak voltage across the membrane. So that's all right!

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