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According to this document on page 3, the formula for Field strength is stated as follows: enter image description here

I can't find reference to this formula elsewhere and was wondering if someone can verify this is correct, in particular where the value of 30 comes from. Thanks.

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    \$\begingroup\$ The \$30\$ comes from the impedance of free space, \$120\pi\$, divided by the area of a sphere, \$4\pi r^2\$ \$\endgroup\$
    – tomnexus
    Commented Feb 6, 2017 at 6:31
  • \$\begingroup\$ The formula is valid for free space, unobstructed paths including clearance for the 0.6 Fresnel zone, but reflections/obstructions of the radiated wave using point-point terrestrial paths can alter the received field intensity significantly from the free space value. \$\endgroup\$ Commented Feb 17, 2021 at 6:20

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The formula the document states is what is called the far field strength of an antenna. The formula is correct. There are plenty of resources on line to check it.

For example:

https://www.semtech.com/uploads/documents/semtech_acs_rad_pwr_field_strength.pdf

http://www.zen22142.zen.co.uk/Theory/antenna.htm

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Imagine a sphere radius \$r\$.

At its centre is an antenna with gain \$G\$ that radiates equally in all directions (isotropic).

Transmitter is fed with \$P \$ watts.

At any point on surface of sphere, power density \$P_d = {{P.G} \over {4 \pi r^2}} \space \bigg[ {W \over m^2} \bigg]\$

Free space impedance \$Z_0 = {E \over H} = 120 \pi \space [\Omega]\$

Therefore \$H = {E \over {120\pi}}\$ and \$E = {120\pi H}\$

\$P_d = EH = E({E \over {120\pi}}) = {E^2 \over {120 \pi}} \space \bigg[ {W \over m^2} \bigg]\$

So, \${P.G \over {4 \pi r^2}} = {E^2 \over {120 \pi}}\$

Hence, \$P = {{4 \pi r^2}E^2 \over {120 \pi}} = {E^2 r^2 \over {30 G}} \space [W]\$

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