2
\$\begingroup\$

I understand what causes oscillation in a negative feedback op amp circuit- when an op amp circuit is not stabilized to have its AB<1 at the frequency whose phase shift is 180, then the negative feedback will turn positive.

I attached the circuit I am working with (not gonna lie, its for school). The point is to mimic a whole op amp system (the amplification is now much bigger hence, is now in danger of instability) and being able to add poles and zeroes to stabilize

Here is what I don't understand-When I input a small sin wave signal at R1,and at the output, I saw the signal magnified by 1/B. Magnifying the signal, I saw, riding on my sin wave, another very small sin wave- these are my oscillations from noise.

enter image description here

Why don't these oscillations take over the signal? If they are created from positive feedback, shouldn't they keep growing? Does it have to do with slew rate?

Thanks

\$\endgroup\$
1
  • \$\begingroup\$ You are speaking of a "circuit" - why don`t you show us the "circuit" ? Which opamp? What do you mean with "stabilized"? What are "oscillations from noise"? Without additional information, no substantial answer is possible. \$\endgroup\$
    – LvW
    Commented Feb 6, 2017 at 8:52

1 Answer 1

3
\$\begingroup\$

Why don't these oscillations take over the signal? If they are created from positive feedback, shouldn't they keep growing?

The main factor that springs to mind here is slew rate limiting.

At some position in the bode plot, the gain is above unity and the phase is at 180 degrees and simplistically, a sine wave would be expected to grow until it swamps everything. But it can't attain an amplitude that is beyond the slew rate limitations of the op-amp. This is why you sometimes see a small amplitude sine wave riding on the back of your signal.

There can be other mechanisms as well but I expect slew rate limiting to be one of the more significant factors.

\$\endgroup\$
3
  • \$\begingroup\$ Yes - I agree that the slew rat will limit the oscillation amplitude. However, a small correction: It is the phase of the loop gain which matters - and this phase will reach the "critical point" if it -360deg (note that the last inverter stage alone produces more than 180deg. for large frequencies). \$\endgroup\$
    – LvW
    Commented Feb 6, 2017 at 13:45
  • \$\begingroup\$ @LvW I answered before the schematic was posted. \$\endgroup\$
    – Andy aka
    Commented Feb 6, 2017 at 13:48
  • \$\begingroup\$ Ahh - OK, I see. \$\endgroup\$
    – LvW
    Commented Feb 6, 2017 at 15:46

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.