What would be the voltage V1? I tried voltage divider :

V1 = (R1+R2/(R1+R2)+(4 R0+ R3 +RT) )


  • \$\begingroup\$ Please show a bit of your own effort in solving this. Don't be afraid to make mistakes, but we are not just giving the answers to your homework. \$\endgroup\$
    – Douwe66
    Commented Feb 7, 2017 at 6:31
  • \$\begingroup\$ @Douwe66 This isn't a question in my HW its a step that I need to analyze other questions, I did try it and I already have an answer but it is wrong, but as you suggested I have edited the question with my answer. \$\endgroup\$ Commented Feb 7, 2017 at 6:42
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    \$\begingroup\$ @user3052793 I just tried to solve it. can you check whether I got correct answer or not. see this. (I'm a student) \$\endgroup\$
    – user105009
    Commented Feb 7, 2017 at 7:26
  • \$\begingroup\$ @KrishnShweta Alright I will solve again and compare. Much appreciated. \$\endgroup\$ Commented Feb 7, 2017 at 7:40
  • \$\begingroup\$ @user3052793 Really? Is it correct? \$\endgroup\$
    – user105009
    Commented Feb 7, 2017 at 7:41

1 Answer 1


As the voltage V1 does not have a common node with Vs, you can not simply use one voltage divider formula, you actually have 2 voltage dividers. By redrawing the circuit that becomes more clear:


simulate this circuit – Schematic created using CircuitLab

So what you need to do is calculate the voltage of both voltage dividers. The voltage difference between the two dividers is V1.

  • \$\begingroup\$ by 2 voltage dividers, you mean the upper part and the lower part of the circuit? I don't know which voltage difference to compute. \$\endgroup\$ Commented Feb 8, 2017 at 8:47
  • \$\begingroup\$ No, in my picture the branch on the right and the one on the left are both voltage dividers. The voltage between R3 and R1 is the first voltage to calculate and the voltage between R0 and R2 is the second voltage. V1 is the difference between those voltages... \$\endgroup\$
    – Douwe66
    Commented Feb 8, 2017 at 9:17

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