# How do I calculated the outputted AC voltage of an H-Bridge inverter

I am trying to build a wireless battery charger. Below is a rough idea of what I want to achieve.

Currently I am having trouble with the inverter circuit that is shown below.

I understand that this inverter circuit is converting DC to AC by using an H-Bridge configuration with the use of MOSFETS, MOSFET Drivers, timer IC and Inverting IC.

My question is how do I calculate the AC Voltage produced by this inverter if I am to supply 12V DC and set the working frequency to 100khz for wireless power transmission through a litz pancake coil?

I know that regular inverters convert 12VDC to 240 VAC with the use of a transformer. I have tried looking at the 74HC4049N inverting IC datasheet and am unable to identify the outputting AC voltage.

I need to know how much AC is produced in order to correctly build a Diode Bridge rectifying circuit on the battery side.

Any Help will be sincerely appreciated.

• Whatever you supply as VCC is impressed (positive and negative) across the coil. So the coil will see 2 X VCC or 24V peak to peak voltage if VCC=12V. Feb 13, 2017 at 20:25
• The output voltage at connector X3 should be a little less than 24Vp-p as John D has said. It seems like you are mixing up the different meanings of "inverter". You are trying to build an inverter that converts power at DC voltage to usually higher AC voltage. 74HC4049 is a logic inverter that invert the logic state from input to output. Two completely different things. Feb 14, 2017 at 1:55