In oscillator circuit, I have faced such LC topologies where between two capacitors, the wire is grounded as shown above.
What I don't understand is why I should ground it. Clearly at the ground point, the current can take either path A or path B (as in diagram). Now at resonance both path offers zero resistance/reactance. Though path B offers zero resistance in all cases. Assuming my inductor is ideal, why should I allow it to be grounded because if current leaks through path B, it means I am having non zero reactance around the circuit. Lets assume the input impedance of the top amplifier with a gain of $$a$$ is very large.
I though on it a lot, but still I don't have any convincing answer for this. Can someone please drop some clues here.