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I designed the bridge rectifier circuit. I wnat to make a full-wave rectification. so, I made a CMOS circuit. I refered to other papers. Figure2. "An ultra-low-voltage self-powered energy harvesting rectifier with digital switch control" Link:

enter image description here

I think this circuit is full-wave rectification. But the result is a half-wave rectifier circuit. Is the result of this graph correct?enter image description here enter image description here

And my theme is Energy Harvesting. So input in mV units. I had input 0.3V but Simulations output is 1V. Why does this result?

Thank you for reading.

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You can't ground the voltage source to the same ground as the output. You should remove the bottom ground and you will also need a load resistance.

Here is a schematic and simulation of a circuit that functions as a full wave bridge rectifier. This was done in LTSpice.

Full Wave Rectifier

Simulation output

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  • \$\begingroup\$ I removed 1 gnd. Also, I added 10Kohm load resistance. But it is still a half-wave rectifier circuit. \$\endgroup\$ – Jeong Jeong Hoon Mar 2 '17 at 4:24
  • \$\begingroup\$ Please update the schematic and probe the other side of the AC source. \$\endgroup\$ – Kevin White Mar 2 '17 at 4:46
  • \$\begingroup\$ I updated the picture as you wish. And my theme is Energy Harvesting. So input in mV units. \$\endgroup\$ – Jeong Jeong Hoon Mar 2 '17 at 4:58
  • \$\begingroup\$ You still have the unwanted ground in your schematic and you haven't probed both sides of the AC source. Your Virtuoso schematic does not match the simplified one. \$\endgroup\$ – Kevin White Mar 2 '17 at 15:11
  • \$\begingroup\$ I modified the circuit. \$\endgroup\$ – Jeong Jeong Hoon Mar 3 '17 at 2:24

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