I designed the bridge rectifier circuit. I wnat to make a full-wave rectification. so, I made a CMOS circuit. I refered to other papers. Figure2. "An ultra-low-voltage self-powered energy harvesting rectifier with digital switch control" Link:

enter image description here

I think this circuit is full-wave rectification. But the result is a half-wave rectifier circuit. Is the result of this graph correct?enter image description here enter image description here

And my theme is Energy Harvesting. So input in mV units. I had input 0.3V but Simulations output is 1V. Why does this result?

Thank you for reading.


You can't ground the voltage source to the same ground as the output. You should remove the bottom ground and you will also need a load resistance.

Here is a schematic and simulation of a circuit that functions as a full wave bridge rectifier. This was done in LTSpice.

Full Wave Rectifier

Simulation output

  • \$\begingroup\$ I removed 1 gnd. Also, I added 10Kohm load resistance. But it is still a half-wave rectifier circuit. \$\endgroup\$ – Jeong Jeong Hoon Mar 2 '17 at 4:24
  • \$\begingroup\$ Please update the schematic and probe the other side of the AC source. \$\endgroup\$ – Kevin White Mar 2 '17 at 4:46
  • \$\begingroup\$ I updated the picture as you wish. And my theme is Energy Harvesting. So input in mV units. \$\endgroup\$ – Jeong Jeong Hoon Mar 2 '17 at 4:58
  • \$\begingroup\$ You still have the unwanted ground in your schematic and you haven't probed both sides of the AC source. Your Virtuoso schematic does not match the simplified one. \$\endgroup\$ – Kevin White Mar 2 '17 at 15:11
  • \$\begingroup\$ I modified the circuit. \$\endgroup\$ – Jeong Jeong Hoon Mar 3 '17 at 2:24

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