0
\$\begingroup\$

I want to use the maximum energy of the supercapacitor for 3.3 powered circuits. Thus, I thought of using step-up voltage regulator like this Can I do this? What are the other suggestions?

\$\endgroup\$
  • \$\begingroup\$ The link is broken. It's this In general, yes you can do this. There are not many other simple options when using super caps. You could put two in series but then you need to worry about balancing them when charging. Even still it's possible they will discharge to less than 3.3V and you may still want to use them so you would need to consider boost-buck topology. Your approach would be simpler. \$\endgroup\$ – AngeloQ Mar 3 '17 at 2:30
  • \$\begingroup\$ Great. I am planning use two supercaps of 2.7 volts ( series or parallel) to get 3.3 volts output. Could you please tell me any boost-buck module? \$\endgroup\$ – user5311361 Mar 3 '17 at 2:50
  • \$\begingroup\$ @AngeloQ And the one I mentioned can take the input of as low as 0.5 volt. That is very efficient as it would still give output 3.3 volts even though supercaps drop down to 0.5 volt. But, would boost-buck take as low as 0.5 volts as an input? \$\endgroup\$ – user5311361 Mar 3 '17 at 2:53
  • \$\begingroup\$ If you use them in parallel, you don't need boost-buck, just boost, like the one you already identified. If you use series, you could go with this regulator. But again, charging those caps becomes non-trivial. \$\endgroup\$ – AngeloQ Mar 3 '17 at 2:55
  • \$\begingroup\$ No, boost-buck would not generally go to as low a voltage as a straight buck. You are probably best to stay with the boost-only method. \$\endgroup\$ – AngeloQ Mar 3 '17 at 2:56

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.