Need to find out the value of V11 (V11 = 4*I9 Volt), as it's a dependent source and it's value is depending on the current through the plain wire W9 of no resistance. I solved this with Mesh current analysis method but I need to learn to be able to solve this using node voltage analysis method too.
Answers from mesh analysis currents and voltage drops of the elements.
I2 = 7 A & V2 = 280 V
I4 = 8 A & V4 = 40 V
I11 = 18 A & V11 = 40 V
I7 = 8 A & V7 = 80 V
My problem: While solving this with node analysis, as this problem belongs to supernode method application where we form 2 equations, one of which is given by difference of the two end nodes equals the voltage source for which I need value of I9 to be written in voltage form. Which I do not know how to form.
Update 2: I learned from some answers here that, it is possible to find the current and voltage values of each element without having to convert I9 to voltage form. Got the answers but they don't match the answers i got in mesh analysis method. Here's what I did.
Considering bottom node as reference and other nodes 'node a', 'node b' and 'node c' respectively from left to right and Vc=-240, I got these two equations..
node a + node c gives
(-19 + Va/40 + (Va-Vb)/5 + Iac) + ((Vc-Vb)/10 - Iac)= 0
=>-19 + Va/40 + (Va-Vb)/5 + Iac + (Vc-Vb)/10 - Iac = 0
=>0.025Va + 0.2Va-0.2Vb -24-0.1Vb = 19 since (Vc=-240)
0.225Va - 0.3Vb = 43 ------(1)
node b eqn.
(Vb-Va)/5 - 2*(Vb-Va)/5 + (Vb-Vc)/10 = 0
=>-(Vb-Va)/5 + (Vb-Vc)/10 = 0
=>-0.2Vb+0.2Va + 0.1Vb-0.1*-240 = 0
0.2Va - 0.1 Vb = -24 ------(2)
Giving me Va=307V and Vb=373V, giving voltage drop across R4=67V which is not the same as returned in mesh analysis method i.e. 40 V.
Please help me get it right or suggest me where I'm going wrong.