I'm trying to analyze the circuit below and I understand that the transistor T201 is acting like an inverter . Am I wrong ? And also why are the two capacitors in parallel at the beginning of the circuit ? I know that there are many parameters to be considered to select a capacitor such as working temp, temp coeff,working voltage ,leakage current etc., but how do they matter for the circuit below? what does "3A" at the input pin mean ? and also what does "10E" and "11G" at the output pins mean ? Thank you
T201 is a dual transistor, there is a PNP and an NPN part. The T201(P) collector will float (so it will be pulled low by the T201(N) and T200 bases). When VDD5 goes low, T201(P) will turn on and the bases of the other two will go high which will in turn pull their collectors low. So I suppose you could say that T201 acts as an inverter, if that's what you meant.
The two caps in parallel are to provide better filtering of high frequency noise. There are lots of other questions on here that go into a lot more detail of why this is done. It's not a matter of temperature coefficients, working voltage, or leakage, it's about frequency response.
The labels you mentioned could be just references perhaps to other parts of the schematics. 10E and 11G don't mean much otherwise. 3A could indicate the expected current at that terminal, but perhaps not. I expect there is not enough information provided to answer that.