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I want powered GSM module from lithium battery and i want switch off from gpio Arduino to sleep power.

My VCC is 3.2-4.2V is used to powered my Arduino and GSM module. But how can I use n-channel mofset or IC to switch on/off the GSM module from gpio Arduino ?

I think about tip120 but after the voltage drop i don't have enough voltage for my GSM module.

I would like to know if exists a IC or transistor to use the same vcc for Vin and Vout , control by gpio 3.2-4.2V ?

Previous answer : Safe base resistor for TIP120

Sorry for my english i'm french Regards

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I suggest you search for load switches, such as this one. Having a FET as the pass element, the voltage drop will be very low. This one is capable of 3A with only about 32mOhm Rdson, and simple logic on/off input.

EDIT: I just looked at the link to the other question and noticed you listed the exact same load switch I linked above. So what was wrong with that?

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  • \$\begingroup\$ I would like to know if exists another way to do that , sorry for duplicate. \$\endgroup\$ – kiki67100 Mar 13 '17 at 14:22
  • \$\begingroup\$ Essentially most high-side load switches are P-ch MOSFETs, so you could make your own from discrete components. These integrated load switches just make things a little easier for you and the cost is still quite low. \$\endgroup\$ – AngeloQ Mar 13 '17 at 14:24
  • \$\begingroup\$ You asked in the question about using an N-ch MOSFET. Do you have some issue with using a P-ch FET? Using a high side switch (i.e. a P-ch FET) allows you to keep the GSM module ground referenced to the Arduino. If you don't use a integrated load switch and 'roll-your-own', you would need a P-ch pass element (MOSFET), and then a N-ch FET or NPN to turn on the P-ch FET. \$\endgroup\$ – AngeloQ Mar 13 '17 at 14:34
  • \$\begingroup\$ Thanks for your additional detail i think i will use integrated circuit. Have a Nice day \$\endgroup\$ – kiki67100 Mar 13 '17 at 15:20
  • \$\begingroup\$ @kiki67100, if AneloQ helped you, please consider accepting or upvoting the answer. \$\endgroup\$ – mkeith Mar 13 '17 at 16:32

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