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Power four circuits from one adapter an output of the adapter is 12v, 3A.

Should I use the Extention cables like the daisy chain, Should I make some connection in series after the adapter to get 4 outputs.

If I applied the following steps there will be no voltage drop on 4 of the circuits?

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If all your 4 devices require 12V power source, and total combined current consumption will not exceed capability of your adapter (3A), then you can use this power adapter to power all 4 devices at the same time.

There will be always some voltage drop in any cable. It just depends on what voltage drop you (or your devices) will accept.

If you want to daisy chain power cable, of course the device which is most distant from power source will have the highest voltage drop. But it all depends on thickness of cables. The voltage drop could be negligible.

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  • \$\begingroup\$ How can I get rid of the voltage drop on any of the device? What should be the thickness required for the daisy chain cable that there should be no drop voltage? \$\endgroup\$ – Awais khan Mar 30 '17 at 10:03
  • \$\begingroup\$ It's not possible to have no voltage drop. You can make it very small by using thick wires. Rule of thumb for low voltages (12V and such): >0.1mm² cross section per m cable length and ampere current. \$\endgroup\$ – Janka Mar 30 '17 at 10:10
  • \$\begingroup\$ @Awaiskhan zero voltage drop is possible only in one case: you'll invent power cable with zero resistance (that is impossible). We all live in real world. Even your power source won't give you exactly 12.00000V. Say your power source will have tolerance +-1%, it means that voltage of your power source will be between 11.88V and 12.12V. So it is not very important if you will have voltage drop like 0.05V in the wires, right? \$\endgroup\$ – Chupacabras Mar 30 '17 at 11:16
  • \$\begingroup\$ @Chupacabras Yes if we have some voltage drop on the cables is fine, I'm searching for an option which is more reliable and efficient for me to use for the circuit, the circuit are using 5v not 12v. \$\endgroup\$ – Awais khan Mar 30 '17 at 11:20
  • \$\begingroup\$ @Awaiskhan you mentioned 12V in your question, not 5V. But it doesn't change the point of my answer. \$\endgroup\$ – Chupacabras Mar 30 '17 at 11:33

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