# Power of AM signal [closed]

I need to calculate the power of the sidebands and the carrier. The carrier is 10*cos(2pi10⁶t) [V] and the modulating is 3*cos(2pi10³t) [V]. The modulated signal is 10*cos($w_0$t)+$\frac{3}{2}$*cos($w_0$t+$w_m$t)+$\frac{3}{2}$*cos($w_0$t-$w_m$t).

The furthest I can get is to $\frac{m²(t)∗u²}{1+m²(t)∗u²}$ But I can't find what m(t) is.

How can I calculate the percentage of power in the sidebands compared to the total AM power. Thanks in advance.

## closed as off-topic by Matt Young, Wesley Lee, uint128_t, Dmitry Grigoryev, laptop2dApr 4 '17 at 7:16

• This question does not appear to be about electronics design within the scope defined in the help center.
If this question can be reworded to fit the rules in the help center, please edit the question.

• Homework with no attempt at a solution – Matt Young Apr 1 '17 at 23:42
• yep I have an attemp. I get to $\frac{m²(t)*u²}{1+m²(t) * u²}$ – scottbear Apr 1 '17 at 23:47
• @MattYoung but I can't figure out where the m(t) comes from. Not homework but exam study – scottbear Apr 1 '17 at 23:48
• Here is a clue to help you! Think about the Power Spectral Density of the signal. Were you shown how to calculate psd ? – AugustCrawl Apr 2 '17 at 0:21