I would like to measure the voltage drop over a shunt resistor (60mV@60A) and I want to send this voltage signal to ADC with a resolution of 16bit. I want to amplify the signal to obtain better accuracy. I'm going to use the in amp AD620. How do you think I have to connect the shunt with my in amp?

  • \$\begingroup\$ An AD620 is an instrumentation amplifier, not an option amp \$\endgroup\$ – Scott Seidman Apr 3 '17 at 10:50
  • \$\begingroup\$ Looks like 1% (7 bits) is worst-case accuracy. Out of the box, best case, expect 10 bits, what with gain accuracy and offset voltage. Noise Voltage, with bandwidth < 10Hz, is 1uV referred to input, or 80uV in a system of Avcl = 80X used to amplify that 60milliVolt to be 4.8 volts into the ADC. 4.8v/80uV is 6,000 or 12 bits noise. \$\endgroup\$ – analogsystemsrf Apr 3 '17 at 10:59
  • \$\begingroup\$ Have you checked the allowed common mode range of your in-amp? Probably not... \$\endgroup\$ – peufeu Apr 3 '17 at 11:27
  • \$\begingroup\$ @peufeu please can you exaplain why it is important? \$\endgroup\$ – Anto Apr 3 '17 at 11:40
  • \$\begingroup\$ @ScottSeidman do you think it is not good for this application? \$\endgroup\$ – Anto Apr 3 '17 at 11:42

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