0
\$\begingroup\$

Say I have a 12V battery hooked up to an inverter (assume no inefficiency). I guessed that if a 1A, 120V draw was placed on it, because 120W was pulled from the inverter, it would pull 120W, and therefore 12V/10A from the 12V battery. Is this assumption flawed?

\$\endgroup\$
1
  • 1
    \$\begingroup\$ Yes, because your 100% efficiency assumption is not true. \$\endgroup\$ Apr 4 '17 at 15:23
1
\$\begingroup\$

Your assumption is true, power is conserved if you have a 'magical' inverter that converts energy at 100% efficiency.

For a real world inverter however, you need an efficency rating, usually 80-95% but could be lower. For a real world inverter the power out can only be lower than the power in, and if your doing any kind of sizing its better to estimate the efficiency with a lower number.

$$ P_{in}*Efficency = P_{out} $$

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.