# Finding the Thevenin resistance

I'm having a little trouble finding the Thevenin resistance equivalent of this circuit. Without the 7.5k resistor, I expect it to be just 15k||15k. Does the 7.5k resistor here act in parallel with the lower 7.5k resistor (to become a 5k resistor) or is it more complicated than that? simulate this circuit – Schematic created using CircuitLab

• The 7.5K would be in parallel with the lower 15K resistor. However we cannot be fully certain if it is truly connected since you did not dot the connections. I even see a small gap at the top of the 7.5K. – Michael Karas Apr 9 '17 at 0:48
• Cover up the right side resistor and focus on the Thevenin for the rest. $V_{TH}=15\:\textrm{V}\cdot\frac{15\:\textrm{k}\Omega}{15\:\textrm{k} \Omega+15\:\textrm{k} \Omega}=7.5\:\textrm{V}$ and $R_{TH}=\frac{15\:\textrm{k}\Omega\cdot 15\:\textrm{k}\Omega}{15\:\textrm{k} \Omega+15\:\textrm{k} \Omega}=7.5\:\textrm{k} \Omega$. That's a voltage and a series resistance. This sources the right side. Does the rest look pretty easy to complete, now? – jonk Apr 9 '17 at 2:11