In MIPS, an I type instruction has the following format.
- bits [31, 26] are for opcode
- bits [25, 21] are for source register
- bits [20, 16] are for transfer register
- bits [15, 0] are for immediates
If the number of registers used is halved, then I will have two extra bits to use for the immediates. And if I'm assuming 2's complement form, then, I have 18 bits. So is my minimum value for the immediate \$-131072\$ and max value \$131071\$?