I am working on a PCB design that should be matched at a characteristic impedance of 50 Ohms. The circuit down converts a 2.4 GHz signal to a signal in the 2 Mhz- 100 Mhz range using a VCO and a mixer. For the board I will be using, I calculated the required trace width to be 1.04 mm but the pad width of the VCO and mixer is 0.30 mm and 0.45 mm respectively. I have used the trace width of 1.04 mm and only narrowed it down to the respective width when connecting to the VCO and mixer. I wanted to know if this will affect the characteristic impedance of my trace and thereby degrade my signal or since the narrowing of the trace only happens at the end of the trace when connecting to the pad, the characteristic impedance will not affected that much by the narrowing?
2.4 GHz has a wavelength in free space of 125 mm and on a PCB it usually reduces to about 2/3 so say 83 mm. Trace lengths shorter than one tenth of a wavelength are usually regarded as not needing to be matched so if the trace length you refer to is less than about 8 mm then don't worry about it.