# How do I use i(t) = c^(dv(t)/dt) and c=q/v and

In this series circuit:

To determine the voltage dropped across each capacitor

The charge stored in a 2 Farad capacitor

The number of charges stored on the capacitor plates

And Determine what value of a new capacitor C that would store the equivalent charge of all the other capacitors

• Are you sure those capacitors are in series? Commented Apr 20, 2017 at 3:58
• Have you tried rearranging the terms in your second equation? Commented Apr 20, 2017 at 4:06
• Consider: 1 farad = 1 coulomb per volt, by definition. Commented Apr 20, 2017 at 14:17

1. The charge on the 2F capacitor can be calculated using the equation Q=CV. Where C=2F and V=9V because voltages across parallel branches are equal. Thus $$Q_{2F}=18C$$
2. The total charge can be found using the same equation. Where C=10F which is the total effective capacitance and V=9V. Thus $$Q_{total}=90C$$
3. Again, total effective capacitance for parallel capacitors is just arithmetic sum. Thus $$C_{total}=10F$$