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In this series circuit: Three capacitors in parallel

To determine the voltage dropped across each capacitor

The charge stored in a 2 Farad capacitor

The number of charges stored on the capacitor plates

And Determine what value of a new capacitor C that would store the equivalent charge of all the other capacitors

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    \$\begingroup\$ Are you sure those capacitors are in series? \$\endgroup\$ – Chupacabras Apr 20 '17 at 3:58
  • \$\begingroup\$ Have you tried rearranging the terms in your second equation? \$\endgroup\$ – WhatRoughBeast Apr 20 '17 at 4:06
  • \$\begingroup\$ Consider: 1 farad = 1 coulomb per volt, by definition. \$\endgroup\$ – Phil Frost Apr 20 '17 at 14:17
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Those capacitors are in parallel, not series. Whenever you have capacitors in parallel, the total effective capacitance is just the arithmetic sum.

  1. The charge on the 2F capacitor can be calculated using the equation Q=CV. Where C=2F and V=9V because voltages across parallel branches are equal. Thus $$Q_{2F}=18C$$

  2. The total charge can be found using the same equation. Where C=10F which is the total effective capacitance and V=9V. Thus $$Q_{total}=90C$$

  3. Again, total effective capacitance for parallel capacitors is just arithmetic sum. Thus $$C_{total}=10F$$

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    \$\begingroup\$ This looks like a homework question. \$\endgroup\$ – Chu Apr 20 '17 at 6:45

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