In my board it may happen to power only one side of the ADuM140x. All the pins on the other one will be completely floating. When the user plugs in a connector also the second side will be powered at 3.3V and the signals pins will be connected to the device too.

I cannot find in the datasheet is such a scenario is allowable. Anyone has any experience on this?

  • \$\begingroup\$ And I wonder what is the state of the outputs in the powered side. \$\endgroup\$ – Mark Apr 20 '17 at 17:16

From the datasheet:

Unlike other optocoupler alternatives, the ADuM1400/ADuM1401/ADuM1402 isolators have a patented refresh feature that ensures dc correctness in the absence of input logic transitions and when power is not applied to one of the supplies.

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Since you haven't provide a schematic (at this time) I can't comment as to what will happen in your case.


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