I am currently going through the MIT 6.002 lecture videos to help prepare me for my upcoming electronics final, and I came across something that I didn't quite understand
url point to the video and the point in time I am confused about
So far I have been understanding the general idea of how the low/high/band pass (and band stop) filters work, and how they can be created. I understood where he got the part of the graph at low frequencies because the inductor becomes a short, the voltage goes across that and very little drops across the capacitor where Vout is being read. What confused me is the next part, where he says at high frequencies the capacitor is a short, which i understood, but to me that meant the voltage drop happens across the capacitor now, not the inductor, and so Vout gets the voltage drop and you have a high pass filter.
I know from other videos, other classes, and the end of the video that the filter is a band pass, but I am having trouble building that intuition, so I was wondering if anyone here can help explain to me what happens to cause that band pass behavior
I could look at the transfer function, which Im sure will get me the answer, but Im really hoping to build up my intuition about these so I can go on and understand more complicated circuits. Thank you for any help!
As a side note: The way the MIT lectures have been teaching me to look at the circuits, and the way I have been from other classes, is that you look at what happens at low frequencies (capacitors go to open, inductors go to short) and high frequencies (the opposite) and see what happens at your Vout (where you are measuring). So far, I have gotten all of the series examples right, but this one is throwing me off. Am I missing something? Also, I keep thinking that voltage across parallel components is the same, which makes me think the 0 at high frequencies makes sense, yet since the voltage is always across at least one path, I expect it to be a band stop with purely that logic... I know Im missing some key logic here!