Before asking my question, I want to show the probe and scope model I use in the simulation:
In the above schematics the section inside the rectangle represents a scope probe set for DC coupling at 10X which is coupled to the scope's inner network C3 R6. I also set the compensation capacitor C4 such that for a very sharp square input the output at the scope end is a sharp square wave as shown in the below plots:
So now I will use this probe and scope model for my question.
The question is about the following task from a lab text:
Here I modelled this follower's input impedance and the probe-scope as follows:
What I understand from this is that, the extreme high input impedance of the opamp's non inverting input will not let us measure it correctly. This is because the max scope impedance is 10Meg and when probed it will be in parallel with the opamp's huge input impedance and the ratio of Vp/Vin will not reveal the opamp's input resistance, it will see the input impedance around 10Meg.
But at high frequencies as the text says the opamp's input capacitance dominates. So it mentioned one can measure the input capacitance by measuring the f3dB point. But probe's and scope's capacitors have big effect on this measurement. So by measuring Vp/Vin I can find the freq. for f3dB point and from the formula f3dB = 1/ (2 * pi * R1 * C1) and I can find C1 which is the opamp's input capacitance. But the problem is that probe's and scope's capacitance are effecting this measurement a lot. I checked with simulation and it doesnt make sense without putting the probe and scope circuitry into account.
The text is confusing and doesnt give an answer to this.
So my question is, is it possible to measure the input impedance here by using the methods mentioned in the text?
uint128_t's answer gave me an idea.
How about if I first measure the 3dB point when probe&scope connected but without opamp and find the total capacitance(caused by the probe-scope system) for 3dB freq. I mean 1Meg and the total capacitance Ctotal will cause 3dB at a freq. we observe supplied by a generator.
And after this now if I also couple the opamp to the system and find again a new 3dB point and a new corresponding corner frequency, and again I can find the new Ctotal lets call this one Ctotal'. Now can we say Copamp=Ctotal'-Ctotal?