I have a very simple question to ask about charging capacitors and no matter what I put into the Google search bar it will not explain it. If I have a capacitor rated at 16 volts. If I put a continuous 9v supply into it will it store 9v or will it combine and eventually charge to its full capacity. What about an 18v supply? Thank you

  • \$\begingroup\$ The cap will charge up to the 9V you put across it. 18V poof, maybe not right away thought. \$\endgroup\$ May 5 '17 at 17:28
  • \$\begingroup\$ Can you please explain further \$\endgroup\$
    – user140052
    May 5 '17 at 17:34
  • \$\begingroup\$ Probably you might want to learn more about basics. Like why the voltage on two components connected is the same one. \$\endgroup\$
    – Eugene Sh.
    May 5 '17 at 17:36
  • \$\begingroup\$ Peter explains it below but it's basically a safety rating. \$\endgroup\$ May 5 '17 at 17:41
  • \$\begingroup\$ read the answers to the question a few rows down... electronics.stackexchange.com/questions/303555/… \$\endgroup\$
    – Trevor_G
    May 5 '17 at 17:45

The rated voltage of a capacitor is the maximum voltage that it can safely withstand. If you apply a higher-than-rated voltage, the capacitor may be damaged or destroyed, as the dielectric breaks down.

A capacitor can only charge up to the applied voltage - it cannot create more voltage than is applied to it.

  • \$\begingroup\$ I will learn more next time. I was just wondering and couldn't figure this out. Thank you so much \$\endgroup\$
    – user140052
    May 5 '17 at 18:03

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