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I was using two op amps with inputs crossed as seen here: enter image description here

to make inverters for stepping up voltage with high efficiency. The design works well, but op amps seem to be only built for low voltages. I am looking to make a royer converter similar to the one shown here: enter image description here

Are there op amps or comparators that can run off 120 or 240 volts? If not, why?

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  • \$\begingroup\$ there are. sorry i can't name you any part numbers, i've seen 150V op-amps before. \$\endgroup\$ – JustJeff Apr 22 '12 at 16:10
  • \$\begingroup\$ What are you actually trying to do? The earliest op-amps were tube circuits and could require, for example, +/- 300 V supplies. But I doubt that will help you. \$\endgroup\$ – The Photon Apr 22 '12 at 16:49
  • \$\begingroup\$ Depending on what they cost, that might help me. \$\endgroup\$ – Alex Eftimiades Apr 22 '12 at 17:05
  • \$\begingroup\$ For an oscillator?! That's a bad mismatch of cost-effectiveness to your design. If you don't need linear behavior in your circuit (e.g. if switching behavior suffices), don't try to use a linear circuit with high voltage. Otherwise you will end up with something expensive that dissipates a lot of power. \$\endgroup\$ – Jason S Apr 22 '12 at 17:43
  • \$\begingroup\$ Well, in fairness, I did ask "or comparator" which would be OK as well. I just noticed that op amps seem to be available for higher voltages than comparators, so op amps seemed to be more likely to exist given my requirements. \$\endgroup\$ – Alex Eftimiades Apr 22 '12 at 17:50
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There are some op amps, like these ones from Apex that can go up to 50 A or 1200 V, but very expensive (the PA89 costs 716 USD here), and I doubt you really need them.

What exactly do you want to do?

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  • \$\begingroup\$ Wow, that is expensive. I doubt I need something that expensive too. I edited the question to include a link to a schematic I am currently working with. I did not want to post it because I had not marked it as answered yet, and it did not seem tasteful to link an unanswered question to another unanswered question (as it could imply I was using this question to siphon people off to my other question.) \$\endgroup\$ – Alex Eftimiades Apr 22 '12 at 16:25

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