2
\$\begingroup\$

This question is related to that one: Can laser diode be operated with lower than specified voltage?

I am driving a laser diode in a current controlled fashion. What actually happens below the lasing threshold?

In experiments, I can clearly observe some "fluorescence". The fluorescence intensity makes up for only ~0.2% of electrical power. Even more interestingly, the fluorescence intensity stagnates at a nearly constant level, independently of current. Also the voltage remains at a constant level.

Can one theoretically predict some sort of curve for the I / V - characteristics of a Laser Diode below threshold? Similar to the shockley equation for ideal diodes?

\$\endgroup\$
1
  • \$\begingroup\$ Not sure fluorescence is the right term, but I've observed this phenomenon as well, and it's an interesting question. For my purposes I never had a need (or time) to explain or characterize it though. \$\endgroup\$
    – John D
    Commented May 11, 2017 at 12:23

1 Answer 1

1
\$\begingroup\$

It's normal for a laser diode to emit (very little) light below threshold current (cf. "Below the threshold current very little light is emitted by the laser structure."). I don't know, though, if there is a (simple) formula describing the P/I dependency in that operating region and also why one would care.

The fact that voltage stagnates is also no surprise: it's just the forward voltage of the laser diode which depends above some thresold only very little on current like in other diodes. So yes, the Shockley equation is a (more or less) suitable I/V equation. Such equations are always based on simplifications/presuppositions (simplified models of reality). Whether they are good enough for your purpose or not depends on your requirements.

\$\endgroup\$
1
  • \$\begingroup\$ Thank you for your answer. I was just curious about what is going on here, since I observed this several times... \$\endgroup\$ Commented May 13, 2017 at 12:53

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.